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• With k=0 and identical valuations, for any n\geq 2, the problem is equivalent to the partition problem, and therefore it is NP-complete.
• With k\geq n-1, the answer is always "yes", and an allocation can be found in polynomial time.
• With n=3 and k=1 and identical valuations, an allocation can be found in polynomial time if it exists.
• n=3 and k=1 and different valuations.

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